Take Total Work = LCM of the given days, then Total Work = Efficiency × Time.
Example: A in 10 days, B in 15 → Total = 30 units; A = 3 units/day, B = 2 units/day.
Same as work, but emptying pipes / leaks have negative efficiency. If a pipe fills in h but takes h with a leak, the leak alone empties a full tank in hours.
A can do a piece of work in 10 days and B can do it in 15 days. How long will they take if both work together?
A is thrice as good a workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days can A alone finish the remaining work?
A and B can complete a piece of work in 12 and 18 days respectively. A begins to do the work and they work alternately one at a time for one day each. The whole work will be completed in
20 men can finish a piece of work in 30 days working 6 hours a day. In how many days can 15 men finish it working 8 hours a day?
A pipe can fill a tank in 15 hours. Due to a leak in the bottom, it is filled in 20 hours. If the tank is full, how much time will the leak take to empty it?
A, B, and C can do a piece of work in 6, 8, and 12 days respectively. Doing the work together, they get an amount of Rs. 1350. What is the share of B in that amount?